Tentukan nilai x 1.³log x=3 2. x log 25=-3 3.x log 1/10=-2

LogaRitMa

a'log b = c ----> b = a^c
^ dibaca pangkat

³log x = 3 ---> x = 3^3 = 27

x'log 25 = -3
25 = x^-3
5^2 = x^-3
(5^2)^(-1/3) = (x^-3)^(-1/3)
5^-2/3 = x
x = 1/³√5²
x = 1/³√25

x'log 1/10 = -2
1/10 = x^-2
(10^-1)^(-1/2) = (x^-2)^(-1/2)
x = 10^1/2
x = √10