jabarkanlah (4a+7)(4a+3)

Aljabar

(4a + 7)(4a + 3)
= 16a^2 + 12a + 28a + 21
= 16a^2 + 40a + 21

(4a + 7)(4a + 3)
= (4a)(4a) + (4a)(3) + (7)(4a) + (7)(3)
= 16a² + 12a + 28a + 21
= 16a² + 40a + 21

maaf kalau salah
semoga membantu