2log4+2log12+2log6+2log2 Tolong dibantu secara panjang

Diketahui,alog b + alog c = alog b.calog b^c = c x alog b

Jawab,2log 4 + 2log 12 + 2log 6 + 2log 2 =
2log 2^2 + 2log 4.3 + 2log 2. + 1 =2 + 2log 4 + 2log 3 + 2log 2 + 2log 3 + 1 =2 + 2 + 1 + 1 + 2log 3.3 =
6 + 2log 3^2 =6 + 2 x 2log 3
Semoga Membantu,,,


Ps : Jawabanya mentok disitu...