Matematika

Pertanyaan

jumlah deretan aritmetika -21,-17,-13,-9 +... + 71 adalah

2 Jawaban

  • a = -21
    b = -17 - (-21) = 4
    Un = 71

    Un = a + (n-1)b
    71 = -21 + (n - 1)4
    71 = -21 + 4n - 4
    71 = 4n -25
    4n = 71 + 25
    4n = 96
    n = 96/4
    n = 24

    Sn = n/2(a + Un)
    S24 = 24/2(-21+ 71)
    S24 = 12 x 50
    S24 = 600

    maka, jumlah deret aritmatika tsb adalah 600
  • a = -21
    b = 4

    un = a + (n-1)b
    71 = -21 + (n-1) 4
    71 = -21 + 4n - 4
    71 = -25 + 4n
    71+ 25 = 4n
    96 = 4n
    n = 96 / 4
    n = 24

    s24 = n/2 (2a+(n-1)b))
    = 24/2 (2(-21) + (24-1)4)
    = 12 (-42 + (23x4))
    = 12( -42+ 92)
    = 12 x 50
    = 600



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