Diketahui fungsi f(x) =ax + b,jika f (2) = -2 dan f (3) = 13,tentukan nilai f(4)

f(x) = ax + b
f(2) = 2a + b = -2
f(3) = 3a + b = 13
lalu kemudian dikurang secara bersusun
-a = -15
a = 15

f(2) = 2a + b = -2
= (2.15) + b = -2
= 30 + b = -2
b = -2-30
b = -32

maka f(4) = 4a + b
= (4.15) + (-32)
= 60 - 32
= 28

f(x)=ax+b
f(2)=2a+b = -2
f(3)=3a+b = 13
-a = -15
a = 15
2a+b = -2
2(15) + b = -2
30 + b = -2
b = -2-30
b = -32

f(4) = ax + b
= 15*4 + (-32)
= 60 - 32
f(4) = 28

maaf kalau salah