Ini caranya gimnaa ya?yg bisa tolong bantu

Jawab : 
[tex]Fe_{2} O_{3} ===\ \textgreater \ 2Fe + \frac{3}{2} O_{2}[/tex] ΔH = +822 kJ/Mol
[tex]3C + \frac{3}{2} O_{2} ===\ \textgreater \ 3CO [/tex] ΔH = - 330 kJ/Mol

∴ ΔH = 822 + (-330) = +492 kJ/Mol