Bantu kak 2 soal dibawah ini menggunakan cara yang tepat dan jelas dan jwbn yg benar

14) jika Log x = p
Log 1000 = 3

4p-p² = 3
0 = p²-4p+3
(p-3)(p-1)
p= 3 dan p = 1

Log x = 3.
x = 1000

Log x = 1
x = 10

x1.x2 = 1000. 10
= 10000

15) x²-4x+10 = 2x+2
x²-6x+ 8. = 0
(x-4)(x-2) = 0
x= 4 dan x = 2

Hp (2, 4)

[tex](4-\log{x})\log{x}=\log{1000}\\4\log{x}-(\log{x})^2=3\\(\log{x})^2-4\log{x}+3=0\\\log{x_1}+\log{x_2}=\frac{-b}{a}\\\log{x_1x_2}=4\\x_1x_2=10^4=10000[/tex]

[tex]^2\log{\left(x^2-4x+10\right)}=^2\log{\left(2x+2\right)}\\x^2-4x+10=2x+2\\x^2-6x+8=0\\(x-4)(x-2)=0\\HP=\{2,4\}[/tex]