sistem persamaan linier tiga variabel 2×+y-z=2 ×+2y+3z=13 3×-y+z=8
Matematika
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Pertanyaan
sistem persamaan linier tiga variabel 2×+y-z=2
×+2y+3z=13
3×-y+z=8
×+2y+3z=13
3×-y+z=8
1 Jawaban
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1. Jawaban Nisei7
2x + y - z = 2 |×3
x + 2y + 3z = 13 |×1
3x - y + z = 8. |×3
6x + 3y - 3z = 6
x + 2y + 3z = 13 +
=> 7x + 5y = 19
x + 2y + 3z = 13
9x - 3y + 3z = 24 -
=> -8x - 5y = -11 |× -
= 8x + 5y = 11
7x + 5y = 19
8x + 5y = 11 -
=> -x = 8
=> x = -8
7(-8) + 5y = 19
-56 + 5y = 19
-56 -19 = -5y
5y = 75
y = 15
2(-8) + (15) - z = 2
-16 + 15 - z = 2
z = -18 + 15
z = - 3