1. |x-3| jika x > 3 2. | 2x-5| jika x <0 3. | 2x -3| = 6 4. |x +3| = |2x-1| 5. |x-6| + |3+2x| = 20
Matematika
Amandafebrilia19
Pertanyaan
1. |x-3| jika x > 3
2. | 2x-5| jika x <0
3. | 2x -3| = 6
4. |x +3| = |2x-1|
5. |x-6| + |3+2x| = 20
2. | 2x-5| jika x <0
3. | 2x -3| = 6
4. |x +3| = |2x-1|
5. |x-6| + |3+2x| = 20
1 Jawaban
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1. Jawaban Vilachi
1. | x-3| jika x> 3
maka | x-3 | > 0
2. |2x-5| jika x<0
Maka |2x-5| > 5
3. |2x-3| = 6
kemungkinan 1. 2x- 3 = 6
x = 4,5
kemungknan 2. 2x-3 = -6
x = -1,5
4. |x+3| = | 2x-1| kuadratkan kedua ruas sehingga,
x^2 + 6x +9 = 4x^2 -4x + 1
3x^2 - 10x -8 = 0
(3x+2) ( x-4) = 0
maka, x = - 2/3
x = 4
5. |x-6| + |3+2x| = 20
uraikan menjadi 4 kemungkinan
kemungkinan 1
x-6+3+2x = 20
x = 7 2/3
kemungkinan 2
x-6 -(3+2x) = 20
x-6-3-2x = 20
x = -29
kemungkinan 3
-(x-6)+3+2x = 20
-x+6+3+2x = 20
x = 11
kemungkinan 4
-(x-6)-(3+2x) = 20
x-6+3+2x = -20
x = -(5 2/3)