Matematika

Pertanyaan

1. |x-3| jika x > 3
2. | 2x-5| jika x <0
3. | 2x -3| = 6
4. |x +3| = |2x-1|
5. |x-6| + |3+2x| = 20

1 Jawaban

  • 1. | x-3| jika x> 3
    maka | x-3 | > 0

    2. |2x-5| jika x<0
    Maka |2x-5| > 5

    3. |2x-3| = 6
    kemungkinan 1. 2x- 3 = 6
    x = 4,5

    kemungknan 2. 2x-3 = -6
    x = -1,5

    4. |x+3| = | 2x-1| kuadratkan kedua ruas sehingga,
    x^2 + 6x +9 = 4x^2 -4x + 1
    3x^2 - 10x -8 = 0
    (3x+2) ( x-4) = 0
    maka, x = - 2/3
    x = 4

    5. |x-6| + |3+2x| = 20
    uraikan menjadi 4 kemungkinan

    kemungkinan 1
    x-6+3+2x = 20
    x = 7 2/3

    kemungkinan 2
    x-6 -(3+2x) = 20
    x-6-3-2x = 20
    x = -29

    kemungkinan 3
    -(x-6)+3+2x = 20
    -x+6+3+2x = 20
    x = 11

    kemungkinan 4
    -(x-6)-(3+2x) = 20
    x-6+3+2x = -20
    x = -(5 2/3)

Pertanyaan Lainnya